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7m^2-46m-21=0
a = 7; b = -46; c = -21;
Δ = b2-4ac
Δ = -462-4·7·(-21)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2704}=52$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-46)-52}{2*7}=\frac{-6}{14} =-3/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-46)+52}{2*7}=\frac{98}{14} =7 $
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